Wednesday, October 15, 2008

Stressed Out Words Of Support

Practice 7. Factors influencing friction solutions



STUDY OF THE FRICTION FORCE







Objective.







study the characteristics of the friction force with
surfaces. See whether or not depends on the contact surface,
weight and / or the characteristics of the materials that compose
.







Material.







- Dynamometer.



- Smooth surfaces of different materials.



- wooden blocks of different shapes.







theoretical basis







The frictional force is a force that always opposes motion
. In this case we study the frictional force between surfaces
. The friction force depends on the press a
body against another and the surface characteristics of contact
. The force that makes the object on the ground in a horizontal plane
equals weight in magnitude and opposite direction. In an inclined plane
this force is equal to P n (
vertical component of weight). Normal is called ( N ) when
perpendicular to the surface. The other factor upon which the frictional force
is the coefficient of friction μ ,
which is determined by the characteristics
of surfaces and its value is experimentally since
depends on many factors such as roughness,
type of materials, surface defects ...







therefore the friction force is expressed by: Fr = μ • N
(Newton)



Notes μ is dimensionless.







operating method








  1. Put the piece of wood supported by more
    face on a given surface area.
    then hooked the dynamometer to taco and put it horizontal.
    Then we always pulling horizontally
    dynamometer seeing what mark when it begins to move the whole
    . Once you start moving, keep trying to pull
    movement speed is uniform (v = constant) and we scored
    marking the dynamometer. Make 3
    measures and calculate the mean value.









  1. repeat the same process with the lower part of the taco
    surface.









  1. repeat points 1 and 2 ° but
    other contact surfaces.









  1. then weighs the wooden block (the dynamometer
    you better). With the calculated weight know what it is Normal (N).
    then calculates for each measure the value of μ.








calculations and results and conclusions.







With the measurements obtained complete the following table:










































Cara
taco



M easure
1 (N)



M easure
2 (N)



M easure 3
(N)



M easure
4 (N)



Average



Normal (N)




coefficient μ



Mayor































Menor








































issues and conclusions.








  1. Does it depend on the friction force of the contact surface
    ? Explain it.









  1. If the object moves faster, keeping constant
    during the journey, "will depend somewhat
    friction force being higher, lower or equal ?









  1. By changing the type of surface contact, how the force varies
    friction while the block is the same? Why
    what?









  1. If aumentásemos body mass, how
    adjust the force of friction?








Can I Feel Wet Before Periods

Practice 7. Factors influencing friction



STUDY OF THE FRICTION FORCE







Objective.







study the characteristics of the friction force with
surfaces. See whether or not depends on the contact surface,
weight and / or characteristics of the materials that compose
.







Material.







- Dynamometer.



- Smooth surfaces of different materials.



- wooden blocks of different shapes.







theoretical basis







The frictional force is a force that always opposes motion
. In this case we study the frictional force between surfaces
. The friction force depends on the
pushes a body with another and the characteristics of
contact surfaces. The force that makes the object on the ground in a horizontal plane
equals weight in magnitude and opposite direction. In an inclined plane
this force is equal to P n (
vertical component of weight). Normal is called ( N ) when
perpendicular to the surface. The other factor upon which the frictional force
is the coefficient of friction μ ,
which is determined by the characteristics of
surfaces and its experimental value, as dependent
many factors such as roughness, type of
materials surface defects ...







therefore the friction force is expressed by: Fr = μ • N
(Newton)



Note that μ is dimensionless.







operating method








  1. Put the piece of wood supported by more
    face on a given surface area. Then
    block hooked to the dyno and put it horizontal.
    Then we always pulling horizontally
    dynamometer seeing what mark when it begins to move the whole
    . Once you start moving, keep trying to pull
    movement speed is uniform (v = constant) and we scored
    marking the dynamometer. Make 3
    measures and calculate the mean value.









  1. repeat the same process with the lower part of the taco
    surface.









  1. repeat points 1 and 2 ° but
    other contact surfaces.









  1. then weighs the wooden block (the dynamometer
    you better). With the calculated weight know what it is Normal (N).
    then calculates for each measure μ value.








Calculations and results and conclusions.







With the measurements obtained complete the following table:










































Cara
taco



M easure
1 (N)



M easure
2 (N)



M easure
3 (N)



M easure 4
(N)



Average



Normal (N)




coefficient μ



Mayor































Menor








































issues and conclusions.








  1. Does it depend on the friction force of the contact surface
    ? Explain it.









  1. If the object moves faster, keeping constant
    during the journey, "will depend somewhat
    friction force being higher, lower or the same?









  1. By changing the type of surface contact, can vary
    the force of friction while the block is the same? Why
    what?









  1. If aumentásemos body mass, how
    adjust the force of friction?








Important Events Of Soccer

-1 º Bachillerato




1






PROBLEMS
Solutions







  1. What
    amount of ZnCl 2 needed to prepare
    3L 0.32 M solution? Atomic masses: Zn = 65.3 u; Cl = 35.5 u.
    Sun: 130.84 g.







  1. 7g is
    KCl dissolved in 51g of water. What is the concentration of this solution
    in% by mass? Sun:
    12'07%.








  1. How many grams of NaOH are there in 50cm 3 0'6M
    dissolution of it? Na = 23U, H = 1u, O = 16U. Sun: 1'2g








  1. is a solution prepared by mixing 90g water and 92g of ethyl alcohol
    CH 3 CH 2 OH. Find:
    a) proximate concentration of alcohol in water, b) moles of alcohol
    c) molality of the solution if the alcohol is the solute
    . Sun: 50'55%, 2 moles; 22'2 molal.








  1. Calculate the grams of glucose (C 6 H 12 O 6)
    that must be dissolved in water 200g
    to prepare a 0.2 molal solution. Sun: 7.2 g.








  1. It has a nickel sulfate solution (II) to
    6% by mass. Calculate the molarity of this solution
    knowing its density is 1.06 g / mL. Ni = 58.5 u; S = 32U, O = 16U Sun: 0.41 M.








  1. Calculate the molarity, normality, molality and mole fraction of solute
    an aqueous solution
    nitric acid to 33.50% by mass and density 1.2 g / mL. Sun: 6.38 M, 6.38 N, 8mm, 0.126.








  1. have a solution 2N H 2 S density 0.95 g / mL. Halla
    concentration: g / L, molarity,% by mass, molality
    , Xs and Xd. Sun: 34g / L, 1M, 3.58%, 1.09 molal, 0.02 and 0.98.








  1. Calculate the concentration in mass%
    a solution of ethyl alcohol (CH 3 2 CH OH) in water, knowing that
    Xs = 0.207. Atomic mass C = 12u, O = 16U, H = 1u.
    Sun: 40%







  1. We
    5M solution of sodium sulfate and 250mL
    want to prepare for another that is 75% and density 0.75 g / mL. a) What volume of solution
    5M we take?; B) How
    the prepare yourself? Na atomic mass = 23, S = 32 O = 16.
    Sun: 198mL.










  1. The
    commercial sulfuric acid has a density of
    1.84 g / mL and a concentration of 18.1 M. a) Calculate his wealth
    in percent by mass; b) How many mL of the solution above
    will be needed to prepare 2L
    0.4 N solution? Sun: 96.4%, 22.1 mL.








colligative properties of solutions:







  1. The radiator
    a car contains 6L water and supplemented with 4kg
    glycol CH 2 OH-CH 2 OH (M = 62U).
    want to know the temperature at which freeze the mixture. Kc = 1.86. Sun:
    -20 º C.



  2. A solution containing 4.5 g of a substance in water 125g
    frozen at - 0.372 ° C. Calculated molecular mass of solute
    . Kc = 1.86. Sun: 180u



  3. Calculate the freezing temperature of a solution
    produced by dissolving 10 g of sucrose (M = 342u) in 500 g of water.
    Kc = 1.86. Sun:
     0.11 º C


  4. The
    Nicotine is a compound of formula
    empirical
    (C 5 H 7 N) n. Find its molecular formula
    knowing that
    dissolve 0.5 g of the substance in 12g of water, the resulting solution
    boils at 100.14 ° C at normal pressure. Ke = 0.52. C = 12u, 14u
    N =, H = 1u Sun: C
    10 H 14 N 2.













































  1. mix is \u200b\u200b
    150cm 3 of hydroxide solution 2M Sodium
    with 50cm 3 other
    0.5 M solution of the base. Follows the molarity of the resulting solution.
    Sun: 1.625 M.
















STOICHIOMETRY






  1. In the combustion of 42

    g carbon dioxide occurs. What volume in CN
    oxygen and air are needed? What
    amount of carbon dioxide is obtained?
    Air has a 21% oxygen. Atomic weights C = 12u, O = 16U. Sun:
    78.4 L of oxygen, air 373'3L; 154g CO 2 .







  1. Al
    heating potassium chlorate gets oxygen and potassium chloride
    . a) Calculate the grams of potassium chlorate needed
    for oxygen 2L in normal conditions;
    c) How many grams of potassium chloride have been found?
    d) What kind of reaction is? Data:
    atomic mass-cas: Cl = 35'5u; K = 39u, O = 16U. Sun: b)
    7'29 g of KClO 3 c) 4'43 g of KCl, d)
    decomposition.








  1. Find the volume of air that cn needed for combustion
    total of 1 kg of coal for 84% of wealth in coal.
    What volume of carbon dioxide at 127 º C and 760 mm pressure
    has occurred? The air is 21% oxygen
    . Sun: 7466.67 L air;
    2296L CO 2 .







  1. Halla
    the purity of a sample containing ammonium sulfate, knowing that if taken
    13'61 g and treated with excess caustic soda
    3'82 liters of ammonia off
    measured at 18 ° C and 745 mm of mercury. Atomic mass S = 32U;
    O = 16U; N = 14u; H = 1u. Sun : 76%.







  1. 10g is
    reacted aluminum oxide with excess hydrochloric acid and obtained
    25g of aluminum chloride .
    estimated yield of the reaction. Atomic masses: Al = 27U;
    O = 16U and Cl = 35.5 u. Sun: 95.5%







  1. The
    reaction between sodium chloride and silver nitrate gives rise to chloride
    silver and sodium nitrate. Assuming that the reaction takes place
    a yield of 65% and we want to obtain 80.04 g
    silver chloride, a) what
    amount of sodium chloride is required? b) What if
    sodium chloride were of a purity of 20%. M: atomic mass:
    Na = 23U; Cl = 35'5u and Ag = 108u, Sun : a) 50'2
    g NaCl, b) 251 g of sample








  1. How many grams of sulfuric acid 90% of wealth
    need to obtain 1 kg of calcium sulfate by reaction
    with slaked lime Ca (OH ) 2 ? S = 32U atomic masses,
    Ca = 40U, H = O = 1U and 16U. Sun: 800'65 g.







  1. Al
    add calcium hydride occurs on water and calcium hydroxide
    shows a gas. a) Write the reaction that takes place
    . b) Calculate the grams of calcium hydride of 87% purity
    that would be required for 2000 L of gas at 25 °
    C and 720 mm Hg. M. atomic H = 1u, Ca = 40U. Sun: 1871.55 g
    CaH 2 .








  1. Calculate the grams of calcium carbide (CaC 2 ) that
    can be obtained from calcium oxide, with 1000 g of carbon 90% of wealth
    if the reaction yield is 70%.
    What volume of carbon dioxide is obtained
    CN? Atomic masses: C = 12u, Ca = 40U. Sun: 1344 g;
    235.2 L.







  1. Find
    the volume of gaseous hydrochloric acid is
    cn obtained by reacting with sulfuric acid
    a sample of 500 g of salt formed in 30% potassium chloride and 70% of
    sodium chloride. Data: atomic masses: Cl = 35'5u;
    Na = 23U; K = 39u. Sun: 179.12 liters.








  1. A 1g sample consisting of sodium carbonate and potassium carbonate
    , treated with acid hydrochloric
    get a mixture of 1.092 g sodium chloride and potassium chloride.
    Calculate the initial mixture composition in per cent of each component
    . Atomic masses: Na = 23U, C = 12u;
    O = 16U; Cl = 35.5 u; K = 39u. Sun: 50% of each.







  1. What
    sulfuric acid may be obtained from 100g
    pyrite. The reactions are unadjusted:
    FeS 2 + O 2
     Fe 2 O 3 + SO
    2, SO 2 + O 2 
    SO 3 ;
    SO 3 + H 2 O 
    H 2 SO 4.
    atomic masses and Fe S = 32U = 56U. Sun : 163.3 g.







  1. The hydrochloric acid
    reacts with silver nitrate
    forming silver chloride and nitric acid.
    Calculate the grams of silver chloride to be formed if
    react completely 25mL of hydrochloric acid solution 2M
    . Atomic mass: Ag = 108u, Cl = 35.5 u.
    Sun: 7.175 g.









  1. reacted was 12 g calcium carbonate
    with excess hydrochloric acid. Calculate: a) The volume of CO
    2 at 20 ° C and 0.9 atmospheres.
    b) The amount of calcium chloride obtained. c) The volume of HCl solution
    16% by mass and density 1.25 g / mL
    be used. d) What kind of reaction
    belong? Data: atomic masses: Ca = 40U; O = 16U, C = 12u;
    Cl = 35.5 u. Sun: a) 3'2 l; b) 13'32 g.
    c) 43.8 mL.








  1. For
    reaction of zinc with AC. hydrochloric
    get zinc and hydrogen chloride. a) What kind of reaction
    is it? b) What volume of hydrochloric acid
    55% by mass and density 1.5 g / mL,
    must react with an excess of zinc to produce
    50L of hydrogen, measured at 32 º C and 760mm Hg. Atomic masses:
    S = 32U; O = 16U, H = 1u. Sun: 177 mL







  1. In
    a flask of 1 liter of oxygen is 0.05 moles and 0.05 moles of hydrogen
    . A spark is produced
    and liquid water. Calculate: a) The moles of water formed, b)
    How many moles of gas remain without reacting? c) What
    is the pressure inside the flask at 0 ° C? d) Indicates the type of reaction
    . Sun:
    a) 0.05 moles of water; b) 0.025 moles; c) 0'56
    atmospheres.








  1. is reacted a mixture of 48g of S and 78.4 g of Fe to produce iron sulfide
    (II) Indicates a) Is there any
    excess reagent?, b) How many grams of ferrous sulphide will
    ? Atomic mass data S = 32U; Fe = 56U. Sun :
    a) Excess of 3.2 g of sulfur., B) 123'2 g FeS.







  1. burning desire is
    78.4 L of methane gas CH 4 CN, using 200g
    oxygen. The reaction produces carbon dioxide and water
    . A) Which reactant is in excess moles
    and how many left? B) Calculate the grams of carbon dioxide
    to be obtained. Atomic masses: C = 12u;
    O = 16U. Sun: 137.5 g 0.375 moles










burn Al
0'42 g of an oil is produced 1'32 g of CO 2
and 0,54 g water. If the density relative to air is 1.45, calculated
molecular formula. (Hint:
average molecular mass of air = 28'8 u) (Sun: C 3 H 6)






In the fuel
n of 0'785 g
an organic compound formed by C, H and O, are obtained 1'5g CO 2 and
0'921 g of water. To vaporize 0'206 g of compound 108 is evicted
mL of air measured over water at 14 º C and 756 mm Hg
. Find the molecular formula of the compound. (Hint:
vapor pressure of water at 14 º C is 12 mm Hg) (Sol (C H 2 O 6).







By analyzing an organic compound results:
40'7% C; 5.1% and 54'2% H O.
solution formed by 11.8 g of compost and 200 mL of water freezes at 93 º C.
-0 Find its molecular formula. (Soln: 4
C 6 H O 4)










Foto De Patricia Manterola En Short

GET THE PERIODIC TABLE

If you want to see click here

Wednesday, October 8, 2008

Leukoplakia Of The Tongue



Helena and Estela believe they have achieved their first objective, is not it?. I recommend this web